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5x^2+18x-215=0
a = 5; b = 18; c = -215;
Δ = b2-4ac
Δ = 182-4·5·(-215)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-68}{2*5}=\frac{-86}{10} =-8+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+68}{2*5}=\frac{50}{10} =5 $
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